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Calculate how many would be expected to weigh less than 11.93 kg by using the above reasoning, the answer would be 363. If 36 were more than 11.93 kg, where/what was the missing koala?

pi/10 < pi/6, cos(pi/10) > sqrt(3)/2, easily shown that sqrt((5 - sqrt5)/8) < sqrt(3)/2 and sqrt((5 + sqrt5)/8) > sqrt(3)/2

Show that 117^(0.4)+pi^(5/3)-e^2.5 is positive.

Not possible to draw another smooth curve going into the third quad because it does not follow the slopes in the last two fields in the second quad near the x-axis. Must look at it closely.

itute stated cos@=cospi/10=0.951approx so cannot be sqrt((5-sqrt5)/8)

check the revised version

Suppose that PQR is a 50-60-70 (respectively) triangle with an interior point X. Let angle PXR = s and angle QXR = t. Find (in terms of s and t) the three angles of any triangle with side lengths equal to PX, QX and RX.

False statement (the sum on the right has x terms), because x is not necessarily a natural number. If x are natural numbers, x^2 is not differentiable.

by the way, I was that student

(s-60), (t-60), (300-s-t)

a^n=3b, na^(n-1)=6b, 0.5n(n-1)a^(n-2)=5b a=3, b=243, n=6

No

I tried k=sqrt(3.5), plotted x and y intercepts and alpha, they are not collinear.

There is only one real x such that P(x)=0. Not three real xs. Meaning of root.

Exactly one real root and no complex roots when k=+/-1. For other real values of k, there are 3 roots according to the Fundamental Theorem of Algebra, one must be real according to the Conjugate Roots Theorem.

If k=1, z^3-3z^2+3z-1=(z-1)^3, if k=-1, z^3+3z^2+3z+1=(z+1)^3, .: exactly one real root each. I think you need to review your question.

3!3!2!

Re: HSC 2018 MX2 Integration Marathon Try replacing both e^x with e^(x^2).

re: HSC Physics Marathon Archive The reaction force as in Newton's third law.

Re: HSC 2015 3U Marathon h=\frac{-\sqrt{2}+\sqrt{10}}{4}d