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No, as the 3 majors actuarial maths and stats is possible due to the fact many core courses for the 3 majors overlap (courtesy of agreements between school of maths and school of business), allowing you to have enough units left to complete the 3 majors. it is not possible to do actuarial, maths...

These courses you have do to. It is best to get them out of the way in the first semester, but they are offered in both. ACCT1501 Accounting & Financial Mgt 1A ECON1101 Microeconomics 1 MGMT1001 Managing Organisations&People As for the maths course, it depends on your major in science...

Actuarial studies is not that hard. It just takes time and consistent effort to grasp concepts. If you can handle engineering maths, you can handle actuarial maths.

I'm currently doing com(actuarial)/sci(maths) and I can tell you there is no significant different coursework to com/adv maths. You can choose the same courses as anyone doing advance maths. In fact, you can get 3 majors (actuarial, maths and stats) if you do com/sci, which is great especially...

Quantitative risk is meant to be mathematical, the textbook goes into detail on how VaR can be calculated parametrically. But the way it is taught means that you don't go through the maths, rather you go through pros and cons of using each methodology. Plus, with modern computer technology, most...

Provided 0 is a part of the domain of f(x) f(0)=-f(-0)=> f(0)=-f(0), (-0=0 obviously) 2f(0)=0 f(0)=0 This immediately implies if f(x) is an odd polynomial, 0 is a root, (x-0)=x is a factor (factor theorem), and hence f(x) is divisible by x. To answer the f(x)=1/x question, it is a...

I did MATH2881 last year. It had absolutely NO maths in it ... i have no idea why it is a maths course. It seems to me it should really be a finance course. You do learn stuff, but nothing really challenging which you cannot read up by yourself. The assessments are basically comprehension...

No tutorial participation mark for maths, but quizzes are usually held in tutorials. They only consider attendance to decide whether you get a pass conceded or a fail (ironic that most people in that scenario wouldn't have attended many tutorials in the first place) And discrete is awesome...

Oops....sorry you're right about the complex numbers. probably should redefine the codomain as the portion of complex numbers z where Re(z)>=0. Yes, the definitions are provided to students via textbooks, but knowing them rigorously is not needed for most part of their examinations and hence...

I agree that definitions are important, except high school maths is currently not rigorous enough to deal with them in detail (for example defining functions without specifying domain and codomain). High school mathematics is just applications, where proving important theorems is rare. Proofs...

Um i think the definition of a function should be raised. From Wolfram: A function is a relation that uniquely associates members of one set with members of another set. A function y=f(x) has critical points at all points x0 where f^'(x0)=0 or f(x) is not differentiable. So f: R -> R (real...

um... try differentiating both answers you got... clearly only the positive case is valid

+1... (2) describes the mindset I had when I was finding real solutions. The fact there are perfect squares mean that x and y should be relatively small square numbers less that 11... hence 9 and 4. Although complex solutions for x and y may exist....

By inspection x=4, y=9

Change (z-1+i)/(z+1-i)=ki to (z-(1-i))/(z-(1+i))=ki --> (z-(1-i))=ki*(z-(1+i)) --> rotation by 90 degrees since k is real. This means the angle between vectors (z-(1-i)) and (z-(-1+i)) is 90 degrees since k is real This is same as sketching Arg[(z-1+i)/(z+1-i)]=pi/2 or -pi where the points...

I assume the denominator is 1-ik Let ABC be the triangle with A,B,C being complex numbers u,v and that fraction (sorry cbf typing it) To show that it is right angled, try showing vector AC=ki*(vector BC) ie. try u-(the fraction) and v-(the fraction), simplify and see what you get

um... just change Q[acos(pi+theta), bsin(pi+theta)] to Q[-acos(theta), -bsin(theta)] with basic 2U trig and its pretty obvious from there. No need for sum or differences of trig formula.

If you want, you can defer MGMT to later years (i think the maths website suggest in third year).

According to the course outline on the maths website, you do discrete maths (MATH1081). Imo, you should do discrete maths instead of MGMT1001, because the main thing you learn in discrete maths is how to construct a formal and rigorous proof, which is very important leading into second year...

You need the course notes for MATH1151 and MATH1251. The course notes include: - Calculus notes and problem booklets - Algebra notes and problem booklet - past exam paper booklet - course outline For around $50, that is a very good deal. All material is written by UNSW Maths Staff...