-
Looking for HSC notes and resources? Check out our Notes & Resources page
1997 HSC Halp! (1 Viewer)
- Thread starter Mudkip94
- Start date
untouchablecuz
Active Member
- Joined
- Mar 25, 2008
- Messages
- 1,693
- Gender
- Male
- HSC
- 2009
Thanks for the quick response but I'm still having some issues 
^2+(q-3)^2)
?
OK.)
I get this.^2+(q-1)^2)
Is this meant to be^2+(q-3)^2)
I get this.^2+(q-1)^2=(p-2)^2+(q-3)^2)
Now I'm stuck. Solve simultaneously as in simultaneous equations? Simultaneous equations with what?
untouchablecuz
Active Member
- Joined
- Mar 25, 2008
- Messages
- 1,693
- Gender
- Male
- HSC
- 2009
Wait... I got P(4, -1)...
-
-1 = 2 * 4 - 9
Therefore P(4, -1) lies on y = 2x - 9
-
(AP)^2 = (4-0)^2 + (-1-1)^2
(AP)^2 = 20
-
(BP)^2 = (4-2)^2 + (-1-3)^2
(BP)^2 = 20
-
AP = BP
Therefore P(4, -1) lies on the line y = 2x - 9 and is equidistant from A and B.
amirite?
-
-1 = 2 * 4 - 9
Therefore P(4, -1) lies on y = 2x - 9
-
(AP)^2 = (4-0)^2 + (-1-1)^2
(AP)^2 = 20
-
(BP)^2 = (4-2)^2 + (-1-3)^2
(BP)^2 = 20
-
AP = BP
Therefore P(4, -1) lies on the line y = 2x - 9 and is equidistant from A and B.
amirite?
ohexploitable
hey
my very first bos maths question
ahhh good times
ahhh good times