• Want to take part in this year's BoS Trials event for Maths and/or Business Studies?
    Click here for details and register now!
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

2007 Q7 (1 Viewer)

DJel

Member
Joined
Dec 3, 2006
Messages
96
Location
Central Coast, N.S.W
Gender
Male
HSC
2008
Could someone please explain to me why we can find the maximum of h (in part (ii)) by simply working it out like so?
3 - 0.4h > 0

- 0.4h > -3

h < 3/0.4

h < 7.5 m

How does the discriminant (I'm assuming that's what we're doing), give you the maximum?

Thanks,

DJel.
 

lost1

Member
Joined
Jun 17, 2006
Messages
60
Gender
Male
HSC
2008
well the question asks to show that: m = 2 (+or-) sqr(3 - 0.4h)

since 'm' is real, the discriminant 3 - 0.4h >= 0

thus h <= 7.5

that is, the value of h has to be less than or equal to 7.5.....ie. 7.5 is max possible height
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top