A motion problem (1 Viewer)

[kooltrainer]

very simple question

as t approach infinite.. what does x approach to?

x = 1/2 tan inverse 2t

 

[pLuvia]

You can also write v in terms of the derivative of x
v=dx/dt=cos²2x

dt=dx/(cos²2x)
t=(tan2x)/2+C

x=[tan^-1(2t-C)]/2 -----> the reason why I didn't put 2C is because that is a constant anyway so C is suffice

dx/dt=1/(1+[2t-C]²)=v

I may have made a mistake somewhere, haven't done this stuff in a year

 

[YannY]

from the inverse tan graph - as t approaches infinite x approaches 1. In your question x is halved hence it approaches 1/2

 

[namburger]

from the inverse tan graph - as t approaches infinite x approaches 1. In your question x is halved hence it approaches 1/2

lol wrong =]
from the tan inverse graph - x approaches pi/2 as t --> infinite
since theres a half therefore pi/4

 

[YannY]

absolutely right - damn you make me feel dumb nam.

Just too smart eh

 

[namburger]

absolutely right - damn you make me feel dumb nam.

Just too smart eh

dww just silly mistake, we just touched inverse functions still got time till our third assesment. gona fail conics half yearlies anyway