Another graph question (1 Viewer)

[BlueGas]

Need help for this question

 

[davidgoes4wce]

Well its being shift horizontally to the left by 3, its been vertically shifted up by 2. So b=-3, c=2. So that rules out A and D.

I think there is something wrong with this question because if you substitute the coordinate (2,3) back into this equation you get a value of a=-1

Here is my working out:

 

[calamebe]

There's no option for a=-1. And you don't really have to do any working out for this one. So here is my method

You see the hyperbola has a negative a because it is in the 2nd and 4th "quadrants" formed by it's asymptotes. B will be -3, as x cannot be 3, and similarly c will be 2 as y cannot be 2. So the only choice that fits all of these is C.

 

[calamebe]

Well its being shift horizontally to the left by 3, its been vertically shifted up by 2. So b=-3, c=2. So that rules out A and D.

I think there is something wrong with this question because if you substitute the coordinate (2,3) back into this equation you get a value of a=-1

Here is my working out:

It isn't given that the coordinate is (2,3), so you can't use it. Just look at it and C will be the only one that makes sense. But I agree the graph is off because subbing a, b and c for x=2 will get (2,4) which is clearly not right.

 

[davidgoes4wce]

It isn't given that the coordinate is (2,3), so you can't use it. Just look at it and C will be the only one that makes sense. But I agree the graph is off because subbing a, b and c for x=2 will get (2,4) which is clearly not right.

I guess I am making an assuming that the coordinate which is pretty much directly on the line is (2,3)

It clearly has to be a negative 'a' value as the curve is a negative hyperbola function.

 

[calamebe]

I guess I am making an assuming that the coordinate which is pretty much directly on the line is (2,3)

It clearly has to be a negative 'a' value as the curve is a negative hyperbola function.

Yeah, thats why I said C.