Answers for HSC04 Astrophysics (1 Viewer)

[trina_288]

Hi, just wondering if anyone could post up some of the answers for this option.
Particularly part d) ii and iii.

Thanks

 

[helper]

d ii)
m₁+m₂=4PI*²r³/GT²
4x10³⁰=4PI*²r³
Gx(6*24*06*60)²x4x10³⁰=4OI*²r³
r³=Gx(6*24*06*60)²x4x10³⁰/4PI*²

 

[helper]

d iii), I will have to check but I think. 2=dwarf

I₁/r₁²=I₂/r₂²
99/r₁²=1/r₂²
r₂²/r₁²=1/99
r₁/r₁=1/square rt 99

 

[trina_288]

Thanks... although i don't understand part iii) Not your answer, the question in general.

 

[helper]

The Intensity of the light coming from a binary system is the sum of the light intensity from the two stars. When one star passess in front of the other, it will eclipse the star.

So when the second star goes in front of the dwarf, the total intensity will drop by the intensity of the dwarf, as no light will be received from it at that point. So the Intensity of that point, gives you the intensity of the main star.

At all other points, the intensity will be the combination of the two.

Have a look at:
http://instruct1.cit.cornell.edu/courses/astro101/java/eclipse/eclipse.htm

 

[trina_288]

thank you! Makes more sense now.