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sxciris89

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what were your answers for the harder parts?
there were sections in the first few
that jst made me stop n go
wtf...o_O;;

wot wer ur answers to
5 - b
5 - c
...and all the rest?
 

u-borat

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5c) i said angle plk=angle pqm(ext angle of cyclic quad equal to opp int angle)
then angle pqm=angle tpm, alternate segment theroem
and tpm=lpk, vertically opposite
therefore plk=lpk and LPK is isoceles.
 

chewnugm

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sxciris89 said:
what were your answers for the harder parts?
there were sections in the first few
that jst made me stop n go
wtf...o_O;;

wot wer ur answers to
5 - b
5 - c
...and all the rest?
5b I had amplitude=2/3 and period t= 2pi/3
5c all angles
TPM = KPL (vertically opposite)
TPM=PQM (angle in the alternate segment)
PQM=KLP (exterior angle to a cyclic quad = interior opposite) or (PLK=180-PQK=PQM)
therefore TPM=KPL=PQM=PLK
therefore KLP is isocele (base angles of isos. triangle are =)
 

sxciris89

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and how many mins were for Q4?
and would i lose marks if i didn put in
"proven by mathematical induction?"
 

bazza159

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i think i got 2 for the amplitude and 2pi/root3 for the period
 

chewnugm

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sxciris89 said:
and how many mins were for Q4?
and would i lose marks if i didn put in
"proven by mathematical induction?"
I had 3 hours 44mins so 12:44PM
 

sakaki.kun

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SHM Answers:

n = 3

a = 2/3

T = 2 pi / 3

Q4 a) ii) 225 mins which equals to 3 hours and 25 mins. Therefore it will be cooked at 12:45pm.
 

independantz

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sakaki.kun said:
SHM Answers:

n = 3

a = 2/3

T = 2 pi / 3

Q4 a) ii) 225 mins which equals to 3 hours and 25 mins. Therefore it will be cooked at 12:45pm.
ditto
 

DrFunk

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it's actually cooked at 12:44, as it said to the nearest minute..

The rough answer if I remember correctly was like 3 hours 44.4 min. rounds down
 

henry08

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DrFunk said:
it's actually cooked at 12:44, as it said to the nearest minute..

The rough answer if I remember correctly was like 3 hours 44.4 min. rounds down
I got the same. It made me hungry and think of lunch lol.
 

lost1

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wa Q6 c (i) & (ii) both (p+q)Cq or something like that?
 

SkimDawg

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Who finished the inverse function? I graphed it but could get rid of the extra fucking y. ive obviously missed something.
 

lost1

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you 'complete the square' with the y terms in one side and then square both sides so you only have one 'y' as the subject
 

friction

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Anyone else prove the MK = ML or whatever it was by congruent triangles ??

Also i had one of the answers and then put a line through it and changed it, will i still get 1 out of 2 ??
 
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friction said:
Anyone else prove the MK = ML or whatever it was by congruent triangles ??

Also i had one of the answers and then put a line through it and changed it, will i still get 1 out of 2 ??
no i used circle geometry
 

chewnugm

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tacogym27101990 said:
no i used circle geometry
Yeah i used circle geometry too. PQ is the diameter of a circle (right angles are produced in a semi circle)
the centre is half the diameter ie M
therefore MK and ML are radii and therefore equal
 

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