Applications of Calculus Qs (1 Viewer)

.ben

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1. Show that the particle whose displacement time equation is S=t3+12 moves from the origin always with a positive acceleration.

2. In a group of 1000 computers linked to each other via the internet, the number N infected with a virus at time t years is give by:

1000
N=-------------
1+Ce-1000t

where C is a constant. Suppose that when t=0 only one computer was infected with the virus. After how many days will 50% of the computers be infected?

3. An antibiotic is developed to kill a selected type of bacterium. In laboratory experiments, the number of bacteria, N and the time t, measured in minutes, are observed to fit the law:

dN
----= -5x10-3
dt

A bacterial count of 200,000 is potentially lethal unless it can be reduced to 100,000 within 3 hours. Is this antibiotic going to be effective? Explain your answer.


4. A pulley is located 25m above a crate which is on the ground at a point O. A 50m rope is passed over the pulley. One end is fastened to the crate and a machine moves the other end along the ground at a constant rate of 4m/s. At any time, let y be the height of the crate from O, and let the distances from the rope end on the machine to O and the pulley be x and d, respectively. How fast is the crate rising when it is 10m above the ground.

THANK YOU.
 
P

pLuvia

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1.
s=t3+12
v=3t2
a=6t
6t>0 (time is always positive)
Then acceleration is always positive

2.
When t=0 N=1
.: C=999
N=1000/(1+999e-1000t)
When half infected therefore N=500
500=1000/(1+999e-1000t)
Using your log rules
t=2.52.. days
t=3 days

Since time is in years you mulitply the decimal answer to 365 to get it into days
 
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.ben

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pLuvia said:
1.
s=t3+12
v=3t2
a=6t
6t>0 (time is always positive)
Then acceleration is always positive

2.
When t=0 N=1
.: C=999
N=1000/(1+999e-1000t)
When half infected therefore N=500
500=1000/(1+999e-1000t)
Using your log rules
t=2.52.. days
t=3 days

Since time is in years you mulitply the decimal answer to 365 to get it into days
thanks so much! silly me i forgot to multiply by 365 to get days!
 

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