Area of trapezium for question 2?? (1 Viewer)

[dnt stop runnin]

wat was the area of the trapezium in question 2 and how did u do it??

 

[Left-ism]

perpendicular height 5root2 times .5 times (the distance of AO plus distance BC)

so its .5*5root2*(root2 plus root72)

which equals 35units squared.

hope that helped..

 

[dnt stop runnin]

yeh it did thanx......thats wat i got,,,,just wanted to make sure