ASAP: can someone explain the derivation of escape velocity formula (2 Viewers)

ExtremelyBoredUser · Feb 9, 2022

lmao1010 said:
^^^

I like to think of it like this;

KE of the object (e.g satellite) needs to be equivalent to the work done for going against the gravitational pull by the body exerting the pull (e.g planet) in order to escape. If KE was less than the potential then it would be inside and if KE was greater it would be outside the pull of the body. The escape velocity is the minimum velocity needed to escape the pull of such body.

$E_{k} = U$
$\frac{mv^{2}}{2} = \frac{GMm}{r}$
$v^{2} = \frac{2GM}{r}$
$v = \sqrt{\frac{2GM}{r}}$

Pretty sure there's others way to interpret the derivation but this one makes sense for me.

lmao1010 · Feb 9, 2022

ExtremelyBoredUser said:
I like to think of it like this;

KE of the object (e.g satellite) needs to be equivalent to the work done for going against the gravitational pull by the body exerting the pull (e.g planet) in order to escape. If KE was less than the potential then it would be inside and if KE was greater it would be outside the pull of the body. The escape velocity is the minimum velocity needed to escape the pull of such body.

$E_{k} = U$
$\frac{mv^{2}}{2} = \frac{GMm}{r}$
$v^{2} = \frac{2GM}{r}$
$v = \sqrt{\frac{2GM}{r}}$

Pretty sure there's others way to interpret the derivation but this one makes sense for me.

thx bro yep the way u have explained makes sense to me as well

ASAP: can someone explain the derivation of escape velocity formula (2 Viewers)

lmao1010

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ExtremelyBoredUser

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lmao1010

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