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calculating pi (1 Viewer)

stag_j

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im just wondering...i know that you can calculate e by finding the sum from 0 to infinity of 1/n!, ie 1/1+1/1+1/2+1/6+1/24....

does anyone know of a similar formula for pi?
 

ezzy85

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measure circumference of a circle with string, measure diameter of that circle and divide circumference by diameter?
 

Affinity

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4 * ( 1 - 1/3 + 1/5 - 1/7 + 1/9 ...) is the only one I can think of now, but it's not a very good one since it's only conditionally convergent.
 

snow bum

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There was some way you could do it empirically, by having a circle in a box with the circle touching each side and finding the probablility of a point being in the circle as opposed to outside the circle but in the box.
 

Affinity

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by the way,
both formulae were obtained from the taylor/maclaurin series expansion of functions.

f(x) = SUM {n=0 -> inf} [( f_n(a) * (x-a)^n ) / n! ]
where a any number.
the approximation for e used f(x) = e^x and a = 0

the approximation for Pi used f(x) = arctan(x) and a = 0
 

Archman

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hmm.. i thought e = lim(n-> infinity) (1+1/n)^n
 

Affinity

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Archman: that's a bad way to find e numerically, converges too slowly..
that's also why the series I posted for Pi was bad.
besides that, It takes much more time on a computer to calculate multiplication -> another reason for not using lim n->inf (1+1/n)^n
 
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