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can someone help me with this space question?? (1 Viewer)

ruwangi

Ru
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Jun 19, 2006
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there is a net force acting on a satelite (m) in a stable orbit around a planet (M) at a distance (R) from the centre of the planet (R)

this net force provides the centripetal acceleration of the satelite

write an expression equating the two forces and hence derive an expression for the period (T1) of a satelite in terms of R, G (universal Gravvitational Constant) and M.

worth 2 marks

thanks
 

Cara.Mel

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a = GM/r^2
a = (4pi^2*r)/T^2 (circular motion equation)

Equate the two so:

GM/r^2 = (4pi^2*r)/T^2
T^2 = (4pi^2*r^3)/GM
T = sqrt((4pi^2*r^3)/GM)

I come from victoria (and like to click the new post button ^_^) so I don't know if there is anything else you need to do, if you had to do anything to get the equations I started from etc, that's the answer anyway :)
 

ruwangi

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Cara.Mel said:
a = GM/r^2
a = (4pi^2*r)/T^2 (circular motion equation)

Equate the two so:

GM/r^2 = (4pi^2*r)/T^2
T^2 = (4pi^2*r^3)/GM
T = sqrt((4pi^2*r^3)/GM)

I come from victoria (and like to click the new post button ^_^) so I don't know if there is anything else you need to do, if you had to do anything to get the equations I started from etc, that's the answer anyway :)

thanks for the help. good luck with the studying :)
 

appleide

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Jun 27, 2006
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If you wanna know where "a = (4pi^2*r)/T^2 (circular motion equation)" came from:
The sum of forces travelling in circular motion directed to the center is:
F=ma=(mv^2)/r
so,
a=(v^2)/r
and v=the perimeter of the circle (2pi*radius) divided by the time taken (period T).
=2pi*r / T

Sub the v into the v^2/r and you'll get it.
 

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