circular functions (1 Viewer)

[lanvins]

1. For pi/2< a < pi with sin a=cos b where 0<b<(pi/2), find a in terms of b

2. For pi/2< a < pi with cos a = -sinb where 0<b<(pi/2), find a in terms of b

thanks

 

[namburger]

1. a= b + pi/2
2. a= b + pi/2