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Run hard@thehsc · Feb 17, 2022

I don't have the answers to these, could someone write what they got so I can confirm where I went wrong. Thanks! @lmao1010 @jimmysmith560 @ExtremelyBoredUser ...

jimmysmith560 · Feb 18, 2022

Part (a) and part (b):

(a) are period of period of rotation of the doject TE I stat 40 Hz 명 - 0.025 s (b) the frequency of rotation is given by, wa

Part (c) and part (d):

c) the length of the arm is given by, d= I 10 m/s 251.3 rad/s -0.0398 m - 0.04 m d abe angular angular veloci ity of the gial

I sadly don't have the answer to part (e), but I hope this helps!

Lith_30 · Feb 18, 2022

for part e) $\omega=\frac{\Delta\theta}{\Delta{}t}$

$\Delta\theta=\frac{\Delta{d}}{r}$ where d is the distance traveled during time t.

$\therefore\omega=\frac{\Delta{}d}{\Delta{}t}\times\frac{1}{r}=\frac{v}{r}$ where v is the tangential velocity.

hence $v=r\omega$

Using $a_c=\frac{v^2}{r}$

$\\a_c=\frac{r^2\omega^2}{r}\\\\a_c=r\omega^2\\a_c=0.0398\times(251.3)^2\\a_c= 2513.44\ \text{m/s}^2$

Run hard@thehsc · Feb 18, 2022

Thanks guys - I got the same answers

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Run hard@thehsc

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