K kevda1st Member Joined Sep 10, 2008 Messages 126 Gender Male HSC 2009 Feb 15, 2009 #1 P ( a sec θ , b tan ) lies on the hyperbola x^2/a^2 - y^2/b^2 = 1 with foci S and S' (+/- ae , 0) a) show that PS= a(e sec θ -1 ) and PS' = a (e sec θ + 1) b) deduce that |PS - PS' | = 2a
P ( a sec θ , b tan ) lies on the hyperbola x^2/a^2 - y^2/b^2 = 1 with foci S and S' (+/- ae , 0) a) show that PS= a(e sec θ -1 ) and PS' = a (e sec θ + 1) b) deduce that |PS - PS' | = 2a
K kevda1st Member Joined Sep 10, 2008 Messages 126 Gender Male HSC 2009 Feb 15, 2009 #2 nvm, found out how to do it after looking at the sticky solutions.
Aerath Retired Joined May 10, 2007 Messages 10,169 Gender Undisclosed HSC N/A Feb 15, 2009 #3 Haha - sticky solutions?
K kevda1st Member Joined Sep 10, 2008 Messages 126 Gender Male HSC 2009 Feb 15, 2009 #4 http://community.boredofstudies.org...303/full-cambridge-fitzpatrick-solutions.html