horndog huang 2
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- 2016
Can someone explain to me iii) and iv) ? Thanks bros
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Can someone explain to me iii) and iv) ? Thanks bros
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For part (iii):
dx = f(6) - f(4) = -6, (A_3 = 2*3) \\ \\Since \int_{2}^{4} f'(x)dx = -\int_{0}^{2} f'(x)dx \\ \\ \int_{0}^{2} f'(x)dx = f(2) - f(0) = 4 \\ \\ Given f(0) = 0 \\ \\ \therefore f(2) = 4 \\ \\ \int_{2}^{4} f'(x)dx = f(4) - f(2) = -4 \\ \\ \therefore f(4) = 0 \\ \\ \int_{4}^{6} f'(x)dx = f(6) - f(4) = -6 \\ \\ \therefore f(6) = -6.$)
Note: In the first line, it is negative 6 because A_3 is under the x axis.
With this, part (iv) should be easily graphed since you know the values of the important points and the derivatives at those points (using the given graph).
Note: In the first line, it is negative 6 because A_3 is under the x axis.
With this, part (iv) should be easily graphed since you know the values of the important points and the derivatives at those points (using the given graph).
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