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3x-5/2x+1boongsta said:hey guys test tomorrow one thing i need help with ....
Differentiate with respect to x
3x-5/2x+1
please show all working i really need to see it
thanks heaps
y' = dy/dx = f'(x)boongsta said:Thanks a lot makes perfect sense except im not sure what u mean by (vu'-uv') ... what do the ' things mean?
You need to remember these rules:boongsta said:have u guys got any ideas to remember this easily ... or maybe someone can explain the reasoning behind the solution? its kinda hard to memorise this
that just complicates things so much its not funny. sorry, but i had to say. what dreamerish said is all you need to know, in perfect format.Templar said:Chain rule...dy/dx = dy/du * du/dx
Or, f(x)=g(h(x))
f'(x)=g'(h(x))*h'(x)
'boongsta said:hey guys test tomorrow one thing i need help with ....
Differentiate with respect to x
3x-5/2x+1
please show all working i really need to see it
thanks heaps
boongsta said:hey guys test tomorrow one thing i need help with ....
Differentiate with respect to x
3x-5/2x+1
please show all working i really need to see it
thanks heaps