differentiating exponentials (1 Viewer)

[onebytwo]

please help to differentiate:

(i) e^(x+logx)

(ii) 3^(-1/x)

i thought i could do them, but my answers are different to the back.

 

[onebytwo]

dont worry about the first one, i got it

 

[pLuvia]

(i)d/dx[e^(x+logx)=(1+1/x)[e^(x+logx)

(ii)d/dx[3^(-1/x)]
=d/dx[e^ln(3(-1/x))
=d/dx[e^(-1/x)ln3]
=[e^(-1/x)ln3][1/x²(ln3)]
=[3^(-1/x)][1/x²(ln3)]

 

[onebytwo]

thats right, thanks heaps