M mtsmahia Member Joined Jun 21, 2008 Messages 284 Gender Male HSC 2010 Oct 3, 2009 #1 Hi Guys can someone help solve these 1) (x^2 + 3) . square root of (2x^3 -5) 2) [x. square root of (x) - x^2 ] / square root of (x + 2) thanks!!
Hi Guys can someone help solve these 1) (x^2 + 3) . square root of (2x^3 -5) 2) [x. square root of (x) - x^2 ] / square root of (x + 2) thanks!!
untouchablecuz Active Member Joined Mar 25, 2008 Messages 1,693 Gender Male HSC 2009 Oct 4, 2009 #2 this method is beyond the 2 unit syllabus (its 4 unit) but knowing this will certainly give you the edge over other 2unit-ers take note that i use the rule that the the derivative of Ln[f(x)]=f'(x)/f(x) Last edited: Oct 4, 2009
this method is beyond the 2 unit syllabus (its 4 unit) but knowing this will certainly give you the edge over other 2unit-ers take note that i use the rule that the the derivative of Ln[f(x)]=f'(x)/f(x)
we0426 Banned Joined Sep 6, 2008 Messages 63 Location ur house Gender Male HSC 2009 Oct 5, 2009 #3 untouchablecuz said: this method is beyond the 2 unit syllabus (its 4 unit) but knowing this will certainly give you the edge over other 2unit-ers take note that i use the rule that the the derivative of Ln[f(x)]=f'(x)/f(x) Click to expand... ur right..i was gona say i never learnt this..wtfff.......4 a sec i thought omg i am gona fail my maths exam....
untouchablecuz said: this method is beyond the 2 unit syllabus (its 4 unit) but knowing this will certainly give you the edge over other 2unit-ers take note that i use the rule that the the derivative of Ln[f(x)]=f'(x)/f(x) Click to expand... ur right..i was gona say i never learnt this..wtfff.......4 a sec i thought omg i am gona fail my maths exam....