Differentiation Question (1 Viewer)

[Carly_57]

How would I differentiate: 2x² + 5x² -4x / x

Thanks

 

[abcd9146]

did you mean:
(2x³ + 5x² -4x) / x?
just simplify it to: 3x² + 5 -4 and differentiate normally

 

[insert-username]

2x³ + 5x² -4x / x

This can be written as (2x³/x) + (5x²/x) - (4x/x)

That simplifies to 2x² + 5x - 4, which can then be differentiated easily.

Alternative, you can use the quotient rule ( [vu' - uv']/v² - bottom times derivative of top minus top times derivative bottom all over the bottom squared), but it's easier to simplify.


I_F

 

[acullen]

That simplifies to 2x² + 5x - 4, which can then be differentiated easily.

...which when differentiated gives:
d/dx = 4x+5

 

[Riviet]

...which when differentiated gives:
d/dx = 4x+5

Don't write your working like that, d/dx has to go with something to differentiate, so instead you write d/dx (2x²+5x-4) = 4x+5

 

[Mountain.Dew]

Don't write your working like that, d/dx has to go with something to differentiate, so instead you write d/dx (2x²+5x-4) = 4x+5

be careful riviet:
d(2x²+5x-4)/dx OR (d/dx)(2x²+5x-4) , not d/dx(2x²+5x-4)

very minor problem, nothing else.

 

[Riviet]

Yes I know that's how you do it, but it looks better when the d/dx are together, lol.
For all you visual learners:

d (2x²+5x-4) = 4x+5
dx