MedVision ad

Dot product (1 Viewer)

ALOZZZ

New Member
Joined
Aug 7, 2020
Messages
25
Gender
Female
HSC
2021
Hey guys I need help with the following question:
The angle between vector u = i-3j and v=ai+5j is 120 degrees.
Evaluate a to 1.d.p.
 

Qeru

Well-Known Member
Joined
Dec 30, 2020
Messages
368
Gender
Male
HSC
2021
Hey guys I need help with the following question:
The angle between vector u = i-3j and v=ai+5j is 120 degrees.
Evaluate a to 1.d.p.
The dot product is defined as where theta is the angle between the vectors. So


Since there's square roots its a good idea to square both sides


At this point its just a quadratic. Which simplfies to: use the quadratic formula from there.
 

Qeru

Well-Known Member
Joined
Dec 30, 2020
Messages
368
Gender
Male
HSC
2021
What about this question:
Theres a bit of a problem with the question (this is why you don't use MIF lol).The dot product can only be negative if the angle between the two vectors is obtuse.

Ignoring this: so (I'm assuming they meant the angle between the vectors is 150 degrees).

Next let . Then again squaring both sides: using the second definition of the dot product: . You now have two simultaneous equations solve for x and y and your done.
 

CM_Tutor

Moderator
Moderator
Joined
Mar 11, 2004
Messages
2,642
Gender
Male
HSC
N/A
The dot product is defined as where theta is the angle between the vectors. So


Since there's square roots its a good idea to square both sides


At this point its just a quadratic. Which simplfies to: use the quadratic formula from there.
@ALOZZZ - Remember that, in squaring (as Qeru has done), there is the possibility of an extra (and invalid) solution having been introduced. Thus, you need to be careful in deciding whether the solution to the problem is one or both or neither of the solutions of the quadratic. The approach is correct and squaring is necessary, it just means that care is needed to make sure your solution is valid.

In this case, the dot product must be negative (as ) and so the solution of the problem must satisfy .



Both of these solutions satisfy and so both are valid.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top