For Darkfing (1 Viewer)

Drongoski · May 22, 2012

Q2

y = (1+x)^0.25 when x=0, y = 1 when x=15, y=2 x = y⁴ - 1

$V = \pi \int _1 ^2 x^2 dy = \pi \int _1 ^2 (y^4 -1)^2dy = \pi\int _1 ^2 (y^8-2y^4+1)dy \\ \\ = \pi [\frac {y^9}{9} - \frac {2y^5}{5} + y]^2 _1 = \pi[\frac {511}{9} - \frac {62}{5} + 1] unit^3$

Drongoski · May 22, 2012

For Darkfing (1 Viewer)

Drongoski

Well-Known Member

Drongoski

Well-Known Member

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