Antisocial
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- Joined
- Oct 2, 2003
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I've asked the teacher about this after I made a big fuss about it during class (my identity is now revealed to some, no doubt) and he said he'd come up with an answer but... that didn't exactly happen.
The Jacaranda textbook gives an example for working out mass defect of a deuterium nucleus:
The mass of a deuterium atom is 2.014102 u. Therefore, there mass of a deuterium nucleus is 2.014102 - 0.000549 = 2.013553 u (mass of atom - mass of electron). The total mass of an isolated proton and neutron would be 2.015941 u. If this proton and neutron combined to form a deuterium nucleus, they would have to lose 2.015941 - 2.013553 = 0.002388 u. And that is the mass defect.
Right.
Now, in another worked example the book gives...
The mass of a helium atom is 4.002603 u.
Calculate the mass defect of the helium nucleus.
The total mass of the constituents of a helium atom (2 protons, 2 neutrons, 2 electrons) is: 2 (1.007276 + 1.008665 + 0.000549) = 4.032980 u.
Mass defect
= 4.032980 - 4.002603
= 0.030377 u.
That's where I'm confused. Why is it in example 1, the mass of the electrons is subtracted from the total mass of the atom to find the mass defect of the nucleus (which I think makes more sense...) whereas in example 2, they subtracted the mass of the atom from the total mass of its constituents to find the mass defect of the nucleus?
Thanks in advance for taking time to read such a long-winded query when the answer is probably so blatantly obvious.
The Jacaranda textbook gives an example for working out mass defect of a deuterium nucleus:
The mass of a deuterium atom is 2.014102 u. Therefore, there mass of a deuterium nucleus is 2.014102 - 0.000549 = 2.013553 u (mass of atom - mass of electron). The total mass of an isolated proton and neutron would be 2.015941 u. If this proton and neutron combined to form a deuterium nucleus, they would have to lose 2.015941 - 2.013553 = 0.002388 u. And that is the mass defect.
Right.
Now, in another worked example the book gives...
The mass of a helium atom is 4.002603 u.
Calculate the mass defect of the helium nucleus.
The total mass of the constituents of a helium atom (2 protons, 2 neutrons, 2 electrons) is: 2 (1.007276 + 1.008665 + 0.000549) = 4.032980 u.
Mass defect
= 4.032980 - 4.002603
= 0.030377 u.
That's where I'm confused. Why is it in example 1, the mass of the electrons is subtracted from the total mass of the atom to find the mass defect of the nucleus (which I think makes more sense...) whereas in example 2, they subtracted the mass of the atom from the total mass of its constituents to find the mass defect of the nucleus?
Thanks in advance for taking time to read such a long-winded query when the answer is probably so blatantly obvious.