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Geomtrical Application of Differentiation HELP!! (1 Viewer)

RHINO7

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Please help me, I'm having trouble with this question-

Show that f(x)= 1/x3 has no stationary points. That is x to the power of 3.
 
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Forbidden.

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You don't need working out to explain.

Anything divided by zero is undefined.

Now to find a stationary point of something the function must equal zero.

Now place any non-zero value in 1/x3and you will always get a non-zero answer, always.

The only way to attempt to get zero from 1/x3 is by placing 0 in the denominator. But dividing by zero is not allowed. So there is NO stationary points.


Mathematically I'd write:

f(x) = 1/x3

dy/dx = 0

1/x3 = 0

But x cannot be equal to zero.

.: 1/x3 has no stationary points.
 
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f (x) = x^(-3)

f ' (x) = -3 (x^[-4])

Stat point is where f'(x)= 0

-3 (x^[-4]) = 0

Someone else can give proper reasoning but basically you cant solve for x in that equation and that's why there is no stationary point..
 

pc4pc

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watatank said:
f (x) = x^(-3)

f ' (x) = -3 (x^[-4])

Stat point is where f'(x)= 0

-3 (x^[-4]) = 0

Someone else can give proper reasoning but basically you cant solve for x in that equation and that's why there is no stationary point..
correct. that is assuming rhino7 uses maths in focus, the answer then becomes -3/x^4.
 
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^^ it doesnt matter how the answer is supposed to be set out, the point is that it doesnt have a stationary point

f3nr15 said:
Holy Shit I Forgot To Derive !!!

Omfg F**k U Integrations Trapezoidal Rule Coz U Dont Need To Integrate Yet.
Take it easy integration is like the easiest topic of all the year 12 content you will learn
 

pc4pc

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i know. just incase OP doesn't understand why your answer doesn't match the textbook answer =]
 

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