Graph (1 Viewer)

[jumb]

Question 3) b)

Anyone know how to make a graph look like that? I want to try and work out the answers.

So if anyone knows the template to make graphs look like that, ill give you a well done.

 

[SeDaTeD]

try
y = 6(3^(-x^2/25)) - 2

 

[jumb]

try
y = 6(3^(-x^2/25)) - 2

Wow! Nice work.

 

[SeDaTeD]

No worries.

 

[jumb]

For those curious enough, here's the answers:

Red = original equation.
(i) light blue
(ii) green
(iii) yellow

 

[NothingIsStatic]

Ah thanks for the answers Jumb.

So far so good for me.

 

[tina_goes_doo]

You just made me incredibly happy jumb. I am at least looking for a mark over 6!

 

[Suspense]

Graphing is always a "gimme" topic

 

[fantasia]

yeh graphing questions have always been standard. they've never really asked us to do anything else besides |f(x)}, 1/f(x) etc.

 

[jumb]

Yeah, graphings easy, I love it!

For the question though, alternatively, y = 6e^(-1/23x^2) - 2 produces a similar style graph.

 

[Shuter]

Yep got them all. Might loose a mark because one of my kind of kinks on the 0 instead of being a smooth turning point like it should.

 

[SeDaTeD]

But using 25, it actually cuts the x-axis at +/- 5. Worked it out from the general shape of y=e^-(x^2)

 

[Jase]

It's the dreaded bell curve.

 

[SeDaTeD]

Hahahaa,
Q3b(iv) Plot on the bell curve the point whcih corresponds to you position in the state (121 marks)

 

[psych_girl]

heihei

Yeah, graphings easy, I love it!

For the question though, alternatively, y = 6e^(-1/23x^2) - 2 produces a similar style graph.

no. graph is alway hard.......f....off...