Halving teh Interval/Bisection Method (1 Viewer)

.ben

.ben

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logex=cosx has a root between 1.2 and 1.4, solve to equation to 2 decimal places.

how come when i sub those two values in they're both negative?
 
Mountain.Dew

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.ben said:
logex=cosx has a root between 1.2 and 1.4, solve to equation to 2 decimal places.

how come when i sub those two values in they're both negative?
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make f(x) = cosx - logex, then find f(1.2) and f(1.4). IMPORTANT: ur calculator should be in radians for it to work. :)
 
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