HELP! : 2 Parametric Questions!! (1 Viewer)

kubekoo

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[This is come from 3Units Jones and Couchman Book2 Ex23.5 Q5a and 6c]

Q5a)
If P(2ap,ap^2) and Q(2aq,aq^2) are points on the parabola x=2at, y=at^2, and S is the focus, prove that PS+SQ=a(p^2 +q^2 +2).

and Q6

i know how to do the first 2 parts,

a) A stright line through T(0,-a) cuts the parabola x^2=4ay at P and Q with respective parameters p and q.
Show that the equation of TP is 2py=x(p^2 + 1) - 2ap
b) Prove that for TP to pass through Q, pq=1

and the part i can't do is the following!! ><~

c) Hence prove that 1/SP + 1/SQ = 1/a

><!!! looking forward to heard from any of your guys!~! thanks!!!
 

withoutaface

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5a) using the focus directrix definition of a parabola, and a diagram, clearly:
SP=ap<sup>2</sup>+a
SQ=aq<sup>2</sup>+a
&there4; SP+SQ=a(p2+q2+2)

6c) 1/SP+1/SQ= (SP+SQ)/SP.SQ=a(p2+q2+2)/(ap2+a)(aq2+a)
=a(p2+q2+2)/a<sup>2</sup>(p<sup>2</sup>+q<sup>2</sup>+1+p<sup>2</sup>q<sup>2</sup>)
=a(p2+q2+2)/a<sup>2</sup>(p2+q2+2) [since pq=-1 &there4; p<sup>2</sup>q<sup>2</sup>=1]
=1/a
 

kubekoo

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withoutaface said:
5a) using the focus directrix definition of a parabola, and a diagram, clearly:
SP=ap<sup>2</sup>+a
SQ=aq<sup>2</sup>+a
&there4; SP+SQ=a(p2+q2+2)
um~~~ directrix defintion ?!??! i never remember comes across to that before, can u please explain a bit more !!! thx thx thx!!!!
 

kubekoo

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kubekoo said:
um~~~ directrix defintion ?!??! i never remember comes across to that before, can u please explain a bit more !!! thx thx thx!!!!
LOL!!!! thanks ~ I understand now!!!

I am assuming the definition of a parabola is ~ the point is equal distance from a fixed point (focus) and a fixed line (directrix)~
therefore, PS=PM where M is the point P projected onto the directirx!!!~

Thanks you very much!!!!!!!!!!!!!!!!!!
 

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