help needed (1 Viewer)

[BoganBoy]

if 4x+3y-60=0 and both axis are the tangent of a circle, find the radius of a cirle.

can sumone please please help? THANKS

ive just edited by question cos i had a typo. thanks.

 

[acmilan]

Do you mean 4x + 3y - 6 = 0?

 

[roxy_chick]

use the perpendicular distance formula to find the distance( radius) from the line to the centre (let the centre be something like (a,b)...) then use it again to find the distance (radius) from the line x=0 and from line y=o. you will then have three euations and three unknown... a,b and r. use subsitution to figure out these unknownss... hope it helps...(btw...I havnt tried thid method for your question..so i hope it works...)

 

[roxy_chick]

you could also try integrating the equation that you were given and using the fact that y=0 and x=0 lie on the circle... to find the equation of the circle...which will then give you the radius...

 

[BoganBoy]

ive tried to use your method, but got stuck when calculating distance from centre to x=0 and y=0. can anyone help me? im like a bit slow.

 

[SaHbEeWaH]

if 4x+3y-60=0 and both axis are the tangent of a circle, find the radius of a cirle.

can sumone please please help? THANKS

ive just edited by question cos i had a typo. thanks.

if it's a tangent to the x and y axes, then the center of radius lies on the line y = x

so let the center of the circle be (x_c,x_c)
x_c is the radius
perpendicular distance between center and tangent (which is the radius)
x_c = |4x_c + 3x_c - 60| / 5 (equal radii)
5x_c = |7x_c - 60|

5x_c = 7x_c - 60
OR 5x_c = -7x_c + 60
so the radius is 5 units or 30 units

 

[BoganBoy]

wow, THANKS MAN, thanks a lot. got it now. thanks