Help please (1 Viewer)

stormz89

Member
Joined
Sep 24, 2007
Messages
132
Gender
Undisclosed
HSC
2008
aww man you have to use function of a function rule given that log f(x) = f'(x)/f(x)
 

hoochiscrazy

Member
Joined
Mar 9, 2008
Messages
60
Gender
Male
HSC
2008
stormz89 said:
aww man you have to use function of a function rule given that log f(x) = f'(x)/f(x)
lol shit yeah i remember now!

edit: done it now lol thx for the reminder!
 
Last edited:
Joined
May 16, 2008
Messages
61
Gender
Female
HSC
2008
hoochiscrazy said:
k i got another for you guys now lol

find dy/dx given that y=ln(2x+1/3x-7)

well known as one of the log laws is ln(a)-ln(b) = ln(a/b)

so you can seperate them, this will give you...

y=ln(2x+1)-ln(3x-7)... get it?
so .

dy/dx=2/(2x+1)-3/(3x-7)

and yeh you simplify that onwards.:D

just reply if u need more help
 

stormz89

Member
Joined
Sep 24, 2007
Messages
132
Gender
Undisclosed
HSC
2008
michelle.leung2 said:
well known as one of the log laws is ln(a)-ln(b) = ln(a/b)

so you can seperate them, this will give you...

y=ln(2x+1)-ln(3x-7)... get it?
so .

dy/dx=2/(2x+1)-3/(3x-7)

and yeh you simplify that onwards.:D

just reply if u need more help
your awsome.

and you get

2(3x-7)-3(2x+1) which you can expand I think
 
Last edited:
Joined
May 16, 2008
Messages
61
Gender
Female
HSC
2008
stormz89 said:
I can do it, its just so long and I've never seen it in any past hsc paper.
then you probs be sure it might be in this years lol

hmmm im still getting there on the question 10 (b)s
do you reckon its going to be a hard paper this year?
;)
 

stormz89

Member
Joined
Sep 24, 2007
Messages
132
Gender
Undisclosed
HSC
2008
michelle.leung2 said:
then you probs be sure it might be in this years lol

hmmm im still getting there on the question 10 (b)s
do you reckon its going to be a hard paper this year?
;)
yes its going to be hard. Like usual.

I plan to just give it a shot and probably give up. Does reading the success one question 10bs work as practise? I might start reading them if it does.
 
Joined
May 16, 2008
Messages
61
Gender
Female
HSC
2008
stormz89 said:
your awsome.

and you get

2(3x-7)-3(2x+1) which you can expand I think
yehh up the top, and the denominator is (2x+1)(3x-7)
then you expand and you should get an answer of...

-17/ (2x+1)(3x-7);)
 
Joined
May 16, 2008
Messages
61
Gender
Female
HSC
2008
stormz89 said:
yes its going to be hard. Like usual.

I plan to just give it a shot and probably give up. Does reading the success one question 10bs work as practise? I might start reading them if it does.
hahaha. i hope not ayy.

the papers arent too bad, just wen we get up to like 10, then i start freaking out, some years i can do but others i cant lol.

dont read.. DO! hahaha.

yeh they give you the model version of the HSC type questions so yeh maybe ayy.
 

stormz89

Member
Joined
Sep 24, 2007
Messages
132
Gender
Undisclosed
HSC
2008
michelle.leung2 said:
hahaha. i hope not ayy.

the papers arent too bad, just wen we get up to like 10, then i start freaking out, some years i can do but others i cant lol.

dont read.. DO! hahaha.

yeh they give you the model version of the HSC type questions so yeh maybe ayy.
fuck your smarter then me. I can only do up to question 6 and not very well. I'll try to do 2004 whole paper with the help of success one but even then I'm still not smart enough.
 
Joined
May 16, 2008
Messages
61
Gender
Female
HSC
2008
stormz89 said:
fuck your smarter then me. I can only do up to question 6 and not very well. I'll try to do 2004 whole paper with the help of success one but even then I'm still not smart enough.

hahaha maths is giving me a headache lol

good luck tomozz ayy.

just try your best
 

stormz89

Member
Joined
Sep 24, 2007
Messages
132
Gender
Undisclosed
HSC
2008
michelle.leung2 said:
hahaha maths is giving me a headache lol

good luck tomozz ayy.

just try your best
yeah you too, aslong as I don't get a band 1 I'm happy.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top