xXnukerrrXx
Member
- Joined
- Feb 17, 2011
- Messages
- 51
- Gender
- Male
- HSC
- N/A
Question 18 of Exercise 4D Year 12 Cambridge Can anyone do it? 
Attachments
Last edited:
-
Finished your HSC? Check out our University Discussion, Non-School forums or help out next year's HSC students! -
YOU can help the next generation of students in the community! Share your trial papers and notes on our Notes & Resources page
help polynomial question (1 Viewer)
- Thread starter xXnukerrrXx
- Start date
nightweaver066
Well-Known Member
- Joined
- Jul 7, 2010
- Messages
- 1,585
- Gender
- Male
- HSC
- 2012
18a)
You can write it out in the form of division transformation.
 = (2x+1)(x-3)Q(x) + 3x - 1)
 \textup{ (by remainder theorem)})
b)
Once again, put it in division transformation form.
 = (x^2-1)Q(x) + 2x - 7)
 = 2 - 7)
 = -2 - 7)
Now using the original equation,
 = x^5 + 3x^3 + ax + b)
 = -5 = 1 + 3 + a + b)
 = -9 = -1 -3 -a + b)
Adding these two equations together,
Therefore
c) = (x^2-5)Q(x) + x + 4)
 = (x^2 - 5)Q(-x) -x + 4)
Add these together,
 + P(-x) = (x^2-5)(Q(x) + Q(-x)) + 8)
So,
Should be that, if it's not i'm not too sure.
You can write it out in the form of division transformation.
b)
Once again, put it in division transformation form.
Now using the original equation,
Adding these two equations together,
Therefore
c)
Add these together,
So,
Should be that, if it's not i'm not too sure.
Last edited:
xXnukerrrXx
Member
- Joined
- Feb 17, 2011
- Messages
- 51
- Gender
- Male
- HSC
- N/A
Answer:
18a) 1/2 b)a=-2 and b=-7 c) 8
18a) 1/2 b)a=-2 and b=-7 c) 8
nightweaver066
Well-Known Member
- Joined
- Jul 7, 2010
- Messages
- 1,585
- Gender
- Male
- HSC
- 2012
b) and c) are correct. a) i'm a little stumped on.
SpiralFlex
Well-Known Member
- Joined
- Dec 18, 2010
- Messages
- 6,960
- Gender
- Female
- HSC
- N/A
The answer should indeed be 
xXnukerrrXx
Member
- Joined
- Feb 17, 2011
- Messages
- 51
- Gender
- Male
- HSC
- N/A
yeh thats what i got before