C cyndi_x3 New Member Joined Mar 14, 2010 Messages 3 Gender Undisclosed HSC N/A Mar 14, 2010 #1 HELP?! please? D: (4x^2 - y^2) / (2x^2 + 3xy - 2y^2 ) x (x^2 + 2xy) / (xy - 2x^2) Thank you heaps in advance
HELP?! please? D: (4x^2 - y^2) / (2x^2 + 3xy - 2y^2 ) x (x^2 + 2xy) / (xy - 2x^2) Thank you heaps in advance
muzeikchun852 Active Member Joined Mar 29, 2009 Messages 1,590 Gender Undisclosed HSC 2011 Mar 14, 2010 #2 the step is: difference of two square / cross-multi x normal factorisation / normal factorisation (2x + y)(2x - y) / (2x - y)(x + 2y) x x(x + 2y) / x(y-2x) take out the common factors: (2x + y) / (y-2x) Last edited: Mar 14, 2010
the step is: difference of two square / cross-multi x normal factorisation / normal factorisation (2x + y)(2x - y) / (2x - y)(x + 2y) x x(x + 2y) / x(y-2x) take out the common factors: (2x + y) / (y-2x)