gentletroll
New Member
- Joined
- Mar 3, 2012
- Messages
- 5
- Gender
- Male
- HSC
- 2012
Thank you in advance if anyone could help me
It's from the 2011 2u maths paper, question 4d (i) and (ii)
The problem is in two parts:
1) Differentiate y = (9-x^2)^(1/2) with respect to x
Fairly sure I'm fine there. Used chain rule and got y' = (1/2)*[(9-x^2)^(-1/2)]*-2x
= -x(9-x^2)^-(1/2)
However, I'm stuck on the second part, which is:
2) hence, or otherwise, find [Integral sign thingy] 6x/(9-x^2)^(1/2) dx
Thank you
It's from the 2011 2u maths paper, question 4d (i) and (ii)
The problem is in two parts:
1) Differentiate y = (9-x^2)^(1/2) with respect to x
Fairly sure I'm fine there. Used chain rule and got y' = (1/2)*[(9-x^2)^(-1/2)]*-2x
= -x(9-x^2)^-(1/2)
However, I'm stuck on the second part, which is:
2) hence, or otherwise, find [Integral sign thingy] 6x/(9-x^2)^(1/2) dx
Thank you
