Hey last question (1 Viewer)

Kutay

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Hey sorry about all he questions but this is the last one and yeh just cant work it out but if can help in anyway thankyou in advance

"A plane is travelling due north at a constant altitude of 10,000m. a house can be seen from the plane on a bearing of 040(deg)True with an angle of depress of 28(deg). Some time later the same house can be seen on a bearing of 113(deg)True with an angle of depression of 50(deg).

(i) Draw Diagram

(ii) Show that the distance travelled by the plane (d) is given by;

d = 10000(cot^2 28 + cot^2 50 - 2cot28cot50 cos73) ^ 1/2
 

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