Make a Difference – Donate to Bored of Studies!
Students helping students, join us in improving Bored of Studies by donating and supporting future students!
How do I do no 2, sorry for sideway image (1 Viewer)
- Thread starter yashbb
- Start date
ExtremelyBoredUser
Bored Uni Student
no need to worry about horizontal component here since the ball is launched directly upwards. You can see this:
u = 12.5
ux = 12.5cos(90) = 12.5 * 0 = 0
uy = 12.5sin(90) = 12.5 * 1 = 12.5
angle is 90 degrees above horizontal.
u = 12.5 ms^-1, after converting kmh^-1 to ms^-1 (just divide by 3.6)
Assume positive to be upwards, negative to be downwards.
(a)
Peak height is when the velocity is 0
v^2 = u^2 + 2gs (since its in the vertical component form)
-u^2 = 2gs
therefore s = - u^2/2g = 7.97 m
(b)
v = u + gt = 12.5 - 9.8(0.5)
= 7.6 ms^-1
(c)
v = u + gt = 12.5 - 9.8(1.5)
= -2.2 ms^-1
u = 12.5
ux = 12.5cos(90) = 12.5 * 0 = 0
uy = 12.5sin(90) = 12.5 * 1 = 12.5
angle is 90 degrees above horizontal.
u = 12.5 ms^-1, after converting kmh^-1 to ms^-1 (just divide by 3.6)
Assume positive to be upwards, negative to be downwards.
(a)
Peak height is when the velocity is 0
v^2 = u^2 + 2gs (since its in the vertical component form)
-u^2 = 2gs
therefore s = - u^2/2g = 7.97 m
(b)
v = u + gt = 12.5 - 9.8(0.5)
= 7.6 ms^-1
(c)
v = u + gt = 12.5 - 9.8(1.5)
= -2.2 ms^-1
once again, you sir, are just too smart.no need to worry about horizontal component here.
u = 12.5 ms^-1
(a)
Peak height is when the velocity is 0
v^2 = u^2 + 2gs (since its in the vertical component form)
-u^2 = 2gs
therefore s = - u^2/2g
(b)
v = u + gt = 12.5 - 9.8(0.5)
(c)
v = u + gt = 12.5 - 9.8(1.5)
ExtremelyBoredUser
Bored Uni Student
If its confusing at first, just draw a diagram of whats going on and list all the known and unknown variables. Then you can see which kinematics equation will work best and solve the question.once again, you sir, are just too smart.
yep ok tyIf its confusing at first, just draw a diagram of whats going on and list all the known and unknown variables. Then you can see which kinematics equation will work best and solve the question.