MedVision ad

HSC 2012 question 11)f)ii) (1 Viewer)

MilkDrinker

Member
Joined
Jan 26, 2012
Messages
137
Gender
Female
HSC
2013
Hi guys,
does anyone here understand this question?
Don't quite get it. I did part i) though.
Thanks
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
It is asking for what values of n is there, that there exists a term in the expansion of (2x^3-1/x)^n, that is constant and NOT zero

(The reason why it says non-zero is because every expansion has a zero constant term since A+0 = A)
 

MilkDrinker

Member
Joined
Jan 26, 2012
Messages
137
Gender
Female
HSC
2013
So how do you know that it is not a zero? I know how to get the term independent of x (i.e. a constant) but how do you know if it is not zero?
 

hjed

Member
Joined
Nov 10, 2011
Messages
211
Gender
Undisclosed
HSC
2013
That expression does not have a constant term for all values of n, they want you to find out which ones it does have a value other than zero for.

You need to use your working in the previous part to determine which values it does have a constant term for.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top