What was the Q. asking to prove/do?good lord
an almost identical question was in my trial, except there was minor difference in the wording (the sequence was in a different order as a GP and a different order as an AP), but I didn't read it properly and ended up doing basically this working out to get a=b=c
a, b, c form an AP with a sum of 9What was the Q. asking to prove/do?
If that's all it said, then 3,3,3 satisfies those conditions (AP with common difference 0 and GP with common ratio 1).a, b, c form an AP with a sum of 9
and then in a different order they form a GP (I *think* it was b, c, a)
I didn't read that bit, and just thought that a,b,c was an AP and a GP and solved it like above and proved it was 3,3,3
but it wasn't
oh well, it was out of 3, and I'll probably still get at least 1 mark for it
I can live with 98%
jk you are rightIf that's all it said, then 3,3,3 satisfies those conditions (AP with common difference 0 and GP with common ratio 1).
Were there some other conditions on the GP or anything?