inequalities (1 Viewer)

[kr73114]

2-x< 1/2(5-2x)

 

[Revelrous]

u = gay
qed

ty ty ty

 

[annabackwards]

Multiply both sides by (5-2x)^2
Move everything to one side, collect the like term (5-2x). Factorise everything. Sketch it and you'll see the answer.

 

[kr73114]

wow, arn't u funny

 

[kr73114]

so what would the solution for x be. or is there no solution?

 

[Revelrous]

wow, arn't u funny

hey hey
hey

go home

 

[annabackwards]

so what would the solution for x be. or is there no solution?

After doing what i said you'll end up with
(5-2x)(4x^2 - 18x + 19) < 0
Consider 4x^2 - 18x + 19 = 0
Using quadratic formula we find that the solutions are
[ 18 +/- sqrt20 ]/ 2(4) = [9 +/- sqrt5 ]/4
Therefore (5-2x)(4x^2 - 18x + 19) < 0 becomes
(5-2x) (4x - [9 +sqrt5 ] ) (4x - [9 - sqrt5 ] ) < 0
Sketching that you'll see that you'll see the parts below the x axis are
(9 -sqrt5) /4< x <5/2 or x > (9 +sqrt5) /4 which is the solution

Usually they aren't this evil and when you factorise they're nice integrals XD