I ibrian Member Joined Mar 21, 2008 Messages 67 Gender Male HSC 2009 Jul 6, 2009 #1 int tan(inverse)x dx fitzpatrick 26d question 36 (i think) cheers
untouchablecuz Active Member Joined Mar 25, 2008 Messages 1,693 Gender Male HSC 2009 Jul 6, 2009 #2 whats d[x(tan^-1x)-0.5In(1+x^2)]/dx
Michaelmoo cbff... Joined Sep 23, 2008 Messages 591 Gender Male HSC 2009 Jul 6, 2009 #3 Im not entirely sure if this will work but: =int tan(inverse)x =- int -sin(inverse)x/cos(inverse)x = -ln[cos(inverse)x] + C hmm. I don't know if these trig laws apply to inverse. We've only just started =\
Im not entirely sure if this will work but: =int tan(inverse)x =- int -sin(inverse)x/cos(inverse)x = -ln[cos(inverse)x] + C hmm. I don't know if these trig laws apply to inverse. We've only just started =\
gurmies Drover Joined Mar 20, 2008 Messages 1,209 Location North Bondi Gender Male HSC 2009 Jul 6, 2009 #4 If you sketch the situation, it will add clarity to my solution.
L lolokay Active Member Joined Mar 21, 2008 Messages 1,015 Gender Undisclosed HSC 2009 Jul 6, 2009 #5 was it a definite integral? you need integration by parts to do this (4 unit), but if it's definite, then you can draw a graph and calculate the integral indirectly (method may come up in 3 unit?)
was it a definite integral? you need integration by parts to do this (4 unit), but if it's definite, then you can draw a graph and calculate the integral indirectly (method may come up in 3 unit?)
I ibrian Member Joined Mar 21, 2008 Messages 67 Gender Male HSC 2009 Jul 7, 2009 #6 ahhh gotcha. yea it was a definate integral. cheers