Integrate Indefinite Integrals Please (1 Viewer)

Utility · Jun 10, 2012

1. 4x / (2x²+3)

2. x - 1 / x²

Timske · Jun 10, 2012

$\int \frac{4x}{2x^2+3} ~\textup{dx} = \ln (2x^2+3) + \textup{C}$
Because, <a href="http://www.codecogs.com/eqnedit.php?latex=\int \frac{f'(x)}{f(x)} ~ dx = lnf(x) @plus; C" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\int \frac{f'(x)}{f(x)} ~ dx = lnf(x) + C" title="\int \frac{f'(x)}{f(x)} ~ dx = lnf(x) + C" /></a>

$\int \frac{x-1}{x^2} ~\textup{dx} = \int \frac{x}{x^2}~\textup{dx} - \int x^{-2}~\textup{dx} \\=\int \frac{1}{x} ~\textup{dx} - \int x^{-2}~\textup{dx}\\=\ln (x) +\frac{1}{x} + \textup{C}$

Integrate Indefinite Integrals Please (1 Viewer)

Utility

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Timske

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