Integration - areas under the cruve (1 Viewer)

[vanush]

Can anyone help me with htis question?

P and Q are the points (2,2.5) and (3,10/9) on the curve y = 10/x². Prove that the area between the arc PQ and the straight line PQ is 5/36 units²

 

[Riviet]

Can anyone help me with htis question?

P and Q are the points (2,2.5) and (3,10/9) on the curve y = 10/x². Prove that the area between the arc PQ and the straight line PQ is 5/36 units²

Find the equation of PQ by finding the gradient of PQ, then using the point-gradient formula. The area between arc PQ and the line PQ is found by finding the area under the interval PQ from x=2 to x=3 and subtracting the area under the curve y=10/x² from the same x boundaries.