C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Jan 16, 2009 #1 Hello, I'm having a problem with the following proving question for integration by parts: Show that ∫cosecx.dx=ln(tan[x/2]) Thanks anyone who can help me. Cheers
Hello, I'm having a problem with the following proving question for integration by parts: Show that ∫cosecx.dx=ln(tan[x/2]) Thanks anyone who can help me. Cheers
J jpmeijer New Member Joined Jun 12, 2007 Messages 16 Gender Male HSC 2008 Jan 16, 2009 #2 jm01 said: I'm having a problem with the following proving question for integration by parts: Click to expand... Are you sure it asked for integration by parts? Because it rolls out quite easily using the substitution t = tan(x/2)
jm01 said: I'm having a problem with the following proving question for integration by parts: Click to expand... Are you sure it asked for integration by parts? Because it rolls out quite easily using the substitution t = tan(x/2)
C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Jan 16, 2009 #3 Uhh, I'll try it with t-results. Thanks
C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Jan 16, 2009 #4 Hello, I still can't prove it using t-results. Could someone please do it me? Thanks
tommykins i am number -e^i*pi Joined Feb 18, 2007 Messages 5,730 Gender Male HSC 2008 Jan 17, 2009 #5 t = tan [x/2] x/2 = atan t 1dx/2 = 1dt/1+t^2 2dt/1+t^2 = dx cosec x = 1/sinx = 1+t^2/2t int cosecx dx = int (1+t^2)/2t*2/(1+t^2) dt = 1/t = ln t + c = ln [tan x/2]
t = tan [x/2] x/2 = atan t 1dx/2 = 1dt/1+t^2 2dt/1+t^2 = dx cosec x = 1/sinx = 1+t^2/2t int cosecx dx = int (1+t^2)/2t*2/(1+t^2) dt = 1/t = ln t + c = ln [tan x/2]