pikachu975
Premium Member
Integral of (5-x^2)dx / sqrt(3-2x-x^2)
By splitting the numerator, thanks for the help!
By splitting the numerator, thanks for the help!
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Integral of (5-x^2)dx / sqrt(3-2x-x^2)
By splitting the numerator, thanks for the help!
Thanks again for the help, can you please show me how to write the (5-x^2) in the form you stated, because I don't quite understand it. Thanks!
Thanks again for the help, can you please show me how to write the (5-x^2) in the form you stated, because I don't quite understand it. Thanks!
I tried it and got a = 1, b = -1, c = 0, but I don't think it's right
I tried it and got a = 1, b = -1, c = 0, but I don't think it's right
5-x^2 = -ax^2 - 2x (a+b) + (3a-2b+c)
So a = 1 by equating coefficients
a+b = 0, so b = -1
3a-2b+c = 5
3 + 2 + c = 5
c = 0
Did I do something wrong?