integration of exponential functions (1 Viewer)

[red802]

can someone teach me how to intergrate these equation

e^4x

and

4xe^x^2 (its really 4xe power of x^2)

can someone teach me how to solve these equation

 

[sasquatch]

∫e^4xdx:

Let y = e^4x

dy/dx = 4e^4x

hence ∫e^4x dx
= (1/4)∫4e^4xdx
= (1/4)∫(dy/dx)dx
= (1/4)y
= (1/4)e^4x

-------------------

4xe^x^2 (its really 4xe power of x^2)

Rewrite it using brackets..cuz im confused...

 

[red802]

sry its, 4xe^(x^2)

 

[Raginsheep]

Firstly consider that:
d/dx e^x2=2xe^x2
Thus
∫4xe^x2dx
=2∫2xe^x2dx
=2e^x2+c

 

[red802]

thank u