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rand_althor

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Hey, I saw I was reading through the 3U marathon and saw the following question:

How exactly do you do this? There was a solution a post or two later which split the parabola into two branches, but I don't understand that method. Can someone please explain?

Also is it possible to find the area between from to ? If so, how do you do it?
 

Drsoccerball

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Hey, I saw I was reading through the 3U marathon and saw the following question:



How exactly do you do this? There was a solution a post or two later which split the parabola into two branches, but I don't understand that method. Can someone please explain?

Also is it possible to find the area between from to ? If so, how do you do it?
you first draw the graph and notice how there is two radiuses you have to rotate around the y axis... You cant just do an instant substitution since you'll rotate the part that you dont want around the axis therefore :








The rest should be easy for you
 
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Drsoccerball

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So the outer radius is the parabola from x=1 to x=2, and the inner radius is the parabola from x=0 to x=1?
The more longer method is to find the two different volumes and subtract one from the other
Its like the question asking you to find the volume bounded by the x axis of ln(x) between 2 and 3....
And the second question is exact same working out as the previous question and exact answer
 

Drsoccerball

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The more longer method is to find the two different volumes and subtract one from the other
Its like the question asking you to find the volume bounded by the x axis of ln(x) between 2 and 3....
And the second question is exact same working out as the previous question and exact answer
Its known as dummy variable (doesn't matter what variable you have) eg:

so the second question is just a demonstration of that
 

Ekman

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The more longer method is to find the two different volumes and subtract one from the other
Its like the question asking you to find the volume bounded by the x axis of ln(x) between 2 and 3....
And the second question is exact same working out as the previous question and exact answer
Well the method that rand_althor is mentioning is basically washer method. You are finding a bigger volume and subtracting from a smaller volume, so it would take exactly the same amount of time.
 

Drsoccerball

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Well the method that rand_althor is mentioning is basically washer method. You are finding a bigger volume and subtracting from a smaller volume, so it would take exactly the same amount of time.
I dont think he knows washers method i mentioned inner and outer radius thats why he said it
 

rand_althor

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I don't know what the washer method is.

Thanks for the help guys!
 

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