integration... special integral question * (1 Viewer)

norelle · Jun 9, 2009

I couldnt get the second question...

up to 2I = integral ln |sec^2日| d日

Is integral ln |sec^2日| d日 = 2sec^2日tan日 / sec^2日 ?

thanksss

Uncle · Jun 9, 2009

tommykins · Jun 9, 2009

bahahah i got the same thing.

lolokay · Jun 9, 2009

dx, not d日
日is a constant

not sure if there should be that 2 in the RHS of the question

Trebla · Jun 10, 2009

$2I = \int_0^{\theta}\ln(\sec^2\theta)\,dx\\\\= \ln(\sec^2\theta) [x]_0^{\theta}\\\\= \theta\ln(\sec^2\theta)\\\\I = \frac{1}{2}\theta\ln(\sec^2\theta)$

I agree with lolokay, perhaps check the question again....

integration... special integral question * (1 Viewer)

norelle

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Uncle

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tommykins

i am number -e^i*pi

lolokay

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Trebla

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