intergration help again ^^ (1 Viewer)

[shuning]

 

[shuning]

the answer is 2pie over 3 square root of 3.

but i got 4 over square root of 3 [pie over 3 - arc tan 2 over square root of 3]

 

[imsleepyz]

use t-result then simplify then complete the square of the denominator t^2+t+1 then it will b a tan inverse and solved

 

[shuning]

use t-result then simplify then complete the square of the denominator t^2+t+1 then it will b a tan inverse and solved

did u even read my 2nd reply?

 

[jet]

 

[shuning]

thanks, lol in my origional i got all the way correct to the last step then fucked up the subbing T.T