u wud be finding the area under the curve, in which u wud change y=ln (x-2) to e^y=x-2P.T.F.E said:aparently i can it was in our 3 unit test!!
(x-2)ln(x-2)-x+C. Do u want the working because this is 4unit integration?P.T.F.E said:intergrate ln(x-2)
Timothy.Siu said:u wud be finding the area under the curve, in which u wud change y=ln (x-2) to e^y=x-2
that question was actually in the 2unit exam this year, exactly the same,