It's late and my brain isn't in tip top shape - how to answer this question? (1 Viewer)

Shadowdude · Oct 31, 2009

This one:

$I\!f \,x=\frac{2ab}{a+b}\, show that \frac{1}{a},\, \frac{1}{x},\, \frac{1}{b}\, are\, in\, an\, arithmetic\, progression.$

jet · Oct 31, 2009

Shadowdude · Nov 1, 2009

Thanks! So basically just equate the two.

Aquawhite · Nov 1, 2009

Well the definitition of an arithmetic progression is defined as there being a common difference between the two. i.e. second - first term = common difference.

Since the diferences are the same - tadah!

It's late and my brain isn't in tip top shape - how to answer this question? (1 Viewer)

Shadowdude

Cult of Personality

jet

Banned

Shadowdude

Cult of Personality

Aquawhite

Retiring

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