Just another simple log question (1 Viewer)

[Miz Janani]

Hey, i know this is probably a simple question but my mind is blank at the moment and i would really appreciate some help..

The question:
log33^2x

Sorry about the bad form

 

[Drongoski]

Hey, i know this is probably a simple question but my mind is blank at the moment and i would really appreciate some help..

The question:
log33^2x

Sorry about the bad form

log₃ 3^2x = 2x (by definition)

log_a a^whatever = whatever

 

[Miz Janani]

Awesome thnx..

And also:
How would i simplify this:

e^4lnx

 

[Timothy.Siu]

Awesome thnx..

And also:
How would i simplify this:

e^4lnx

x^4

 

[Miz Janani]

but how do you get that??

I'm so confused

 

[gurmies]

Simple. e^lna [1]

Proof: Let lna = x

.'. e^x = a.

If you sub in x = lna to [1]

You get e^x, which we have already proved = a.